Question

Resolva as equações, sendo U=Q

Answer 1

$\large\bm{2 - \dfrac{1}{3} \times\left(x + \dfrac{1}{2} \right) = \dfrac{1}{3} - \dfrac{1}{2} \times\left(x - \dfrac{1}{3} \right) } \\\\ \large\bm{2 - \dfrac{1}{3} \times - \dfrac{1}{6} = \dfrac{1}{3} - \dfrac{1}{2} \times \left(x - \dfrac{1}{3} \right)} \\\\ \large\bm{2 - \dfrac{1}{3}x - \dfrac{1}{6} = \dfrac{1}{3}x + \dfrac{1}{6} } \\\\ \large\bm{ \dfrac{11}{6} - \dfrac{1}{3}x = \dfrac{1}{3} - \dfrac{1}{2} x + \dfrac{1}{6} } \\ \\ \large\bm{ \dfrac{11}{6} - \dfrac{1}{3} x = \dfrac{1}{2} - \dfrac{1}{2}x } \\\\ \large\bm{11 - 2x = 3 - 3x} \\ \\ \large\bm{11 - 2x + 3x = 3} \\ \\ \large\bm{ - 2x + 3x = 3 - 11} \\ \\ \large\bm{x = 3 - 11} \\ \\ \bm{\large\boxed{\boxed{  { \large \bm{ x = - 8}}}}}$

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