Question

resolva as equações literais , x^2-cx-6c^2=0​

Answer 1

a=1

b=-c

c=-6c^2

Achando delta

delta=b^2-4ac

delta= (-c)^2-4.1.(-6c^2)

delta=c^2+24c^2

delta=c^2.(1+24)

delta=25c^2

aplicando baskara:

x=[-b+-raiz(delta)]/2a

x=[-(-c)+-raiz(25c^2)]/2.1

x=( c+-5c)/2

x'=(c+5c)/2=6c/2=3c

x"=(c-5c)/2=-4c/2=-2c

raízes para a equação s={-2c; 3c}

Answer 2

Resposta:

S{-2c;3c} tamo junto mano