Question

resolva as equacões irracionais √2×-2=6

Answer 1

Sim!Isto mesmo!............................

Answer 2

$\sqrt{2}x-2=6 \\ \\ (\sqrt{2}x-2)^2=6^2 \\ \\ ( \sqrt{2} x)^2-2.2 \sqrt{2} x+2^2=36 \\ \\ 2x^2-4 \sqrt{2} x+4=36 \\ \\ 2x^2-4 \sqrt{2} x+4-36=0 \\ \\ 2x^2-4 \sqrt{2} x-32=0 \\ \\ x^2-2 \sqrt{2} x-16=0$

Equação de 2º grau resolvendo pela fórmula de Bhaskara

a=1    b=-2$\sqrt{2}$   c=-16

$delta = (-2 \sqrt{2} )^2-4.1.(-16) =4.2+64=8+64=72 \\ \\ \sqrt{delta} = \sqrt{72} = \sqrt{3^2.2^3} =3.2 \sqrt{2} =6 \sqrt{2} \\ \\ x_{1} = \frac{-(-2 \sqrt{2})+6 \sqrt{2} }{2.1} = \frac{ 8\sqrt{2} }{2} = 4\sqrt{2} \\ \\ x_{2} =\frac{-(-2 \sqrt{2})-6 \sqrt{2} }{2.1} = \frac{-4 \sqrt{2} }{2} =-2 \sqrt{2}$

S={-2$\sqrt{2}$;4$\sqrt{2}$}