Question

Resolva as equações exponenciais abaixo:
$( \frac{1}{4}) ^{4x} =0,25  e 4 ^{x}= \sqrt[3]{32}$ 

Answer 1

a)

$( \frac{1}{4} )^4^x=0,25$

$( \frac{1}{4} )^4^x= \frac{25}{100}$

$( \frac{1}{4} )^4^x= \frac{1}{4}$

4x=1
$x= \frac{1}{4}$

b)
$4^x= \sqrt[3]{32}$

$4^x= \sqrt[3]{2^5}$

$2^2^x= 2^{ \frac{5}{3} }$

$2x= \frac{5}{3}$

6x=5

$x= \frac{5}{6}$