Question

resolva as equações exponenciais
a)2×=32
b)5×=625
c)9×=27
d)8×=256
e)25×125
f)(2/3)×=32/243
g)(-1/2)×=1/16
h)4×=1/256
i)7×=1/2401​

Answer 1

Explicação passo-a-passo:

a)2×=32

${2}^{x} = {2}^{5} \\ x = 5$

b)5×=625

${5}^{x} = {5}^{4} \\ x = 4$

c)9×=27

${9}^{x} = {3}^{3} \\ {3}^{2x} = {3}^{3} \\ 2x = 3 \\ x = \frac{3}{2}$

d)8×=256

${2}^{3x} = {2}^{8} \\ 3x = 8 \\ x = \frac{8}{3}$

e)25×125

${5}^{2x} = {5}^{3} \\ 2x = 3 \\ x = \frac{3}{2}$

f)(2/3)×=32/243

$( \frac{2}{3})^{x} = ( \frac{2}{3} )^{5} \\ x = 5$

g)(-1/2)×=1/16

ň existe

h)4×=1/256

${2}^{2x} = {2}^{ - 8} \\ 2x = - 8 \\ x = - 4$

i)7×=1/2401

${7}^{x} = {7}^{4} \\ x = 4$