Question

Resolva as equações do 2°grau.
a) x² + 6x + 9 =0

b) x² - 5x + 6 =0

Answer 1

Resposta:

a)

${x}^{2} + 6x + 9 = 0$

$\Delta = {b}^{2} - 4ac$

$Bhaskara \\ \\ \frac{ - b \frac{ + }{} \sqrt{ \Delta} }{2a}$

$\Delta = {6}^{2} - 4(1)(9) \\ \\ \Delta = 0 \\ \\ x1 = x2 = \frac{ - b}{2a} \\ \\ x1 = x2 = \frac{ - 6}{2(1)} = \frac{ - 6}{2} = - 3$

b)

${x}^{2} - 5x + 6 = 0$

$\Delta = ( { - 5)}^{2} - 4(1)(6) \\ \\ \Delta = 25 - 24 \\ \\ \Delta = 1 \\ \\ \frac{ - ( - 5) \frac{ + }{} \sqrt{1} }{2(1)} \\ \\ \frac{5 \frac{ + }{} 1}{2} \\ \\ x1 = \frac{5 + 1}{2} = \frac{6}{2} = 3 \\ \\ x2 = \frac{5 - 1}{2} = \frac{4}{2} = 2$

Raízes 2 e 3

Bons Estudos!