Question

resolva as equaçoes do 2° Grau.​

Answer 1

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A) Calculando o Δ da equação completa:

Δ = b2 - 4.a.c

Δ = -52 - 4 . 1 . 6

Δ = 25 - 4. 1 . 6

Δ = 1

Aplicando Bhaskara:

x = (-b +- √Δ)/2a

 

x' = (--5 + √1)/2.1     x'' = (--5 - √1)/2.1

x' = 6 / 2     x'' = 4 / 2

x' = 3     x'' = 2

B)

Δ = b2 - 4.a.c

Δ = -12 - 4 . 1 . -6

Δ = 1 - 4. 1 . -6

Δ = 25

Bhaskara:

x = (-b +- √Δ)/2a

 

x' = (--1 + √25)/2.1     x'' = (--1 - √25)/2.1

x' = 6 / 2     x'' = -4 / 2

x' = 3     x'' = -2

C)

Δ = b2 - 4.a.c

Δ = -82 - 4 . 1 . 7

Δ = 64 - 4. 1 . 7

Δ = 36

 Bhaskara:

x = (-b +- √Δ)/2a

 

x' = (--8 + √36)/2.1     x'' = (--8 - √36)/2.1

x' = 14 / 2     x'' = 2 / 2

x' = 7     x'' = 1