Resolva as equações ;
A) x² + x =0 B) 3x² + 7x =0
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A) x² + x =0
x² + x + 0
Δ=b² - 4ac
Δ= 1²- 4.1.0
Δ=1
x= -b +/- √Δ / 2a
x= -1 +/- √1 / 2.1
x'= -1 + 1/2
x'= 0/2
x'=0
x''= -1 -1/2
x''=-2/2
x''= -1
B) 3x² + 7x =0
3x² + 7x +0
Δ=b²-4ac
Δ= 7²-4.3.0
Δ=49
x=-b +/- √Δ / 2a
x= -7 +/- √49 / 2.3
x'= -7 + 7/6
x'= 0/6
x'= 0
x''= -7-7/6
x''= -14/6
x''= -7/3
x² + x + 0
Δ=b² - 4ac
Δ= 1²- 4.1.0
Δ=1
x= -b +/- √Δ / 2a
x= -1 +/- √1 / 2.1
x'= -1 + 1/2
x'= 0/2
x'=0
x''= -1 -1/2
x''=-2/2
x''= -1
B) 3x² + 7x =0
3x² + 7x +0
Δ=b²-4ac
Δ= 7²-4.3.0
Δ=49
x=-b +/- √Δ / 2a
x= -7 +/- √49 / 2.3
x'= -7 + 7/6
x'= 0/6
x'= 0
x''= -7-7/6
x''= -14/6
x''= -7/3
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