Question

resolva as equaçoes a)(x+1)ao 2=7+x b(x-2)ao 2-x=1 etc? alguém sabe? por favor ;)

Answer 1

a(x+1)^2= 7+x
x^2+2x+1-7-x= 0
x^2 +x-6= 0

b) (x-2)^2-x= 1
x^2 -4x+4-x=1
x^2 -5x+3=0

Answer 2

a) (x + 1)² = 7 + x

x² + 1² = 7 + x
x² - x + 1 - 7
x² - x - 6 = 0


delta = (-1)² - 4.1.(-6)
delta = 1 + 24
delta = 25


x = -(-1) ± √25/2.1

x = 1 ± 5/2

x = 1 - 5/2 = -4/2 = -2

x = 1 + 5/2 = 6/2 = 3

s={ -2, 3 }
.
.
.
b) (x - 2)² - x = 1

x² - 2² - x = 1
x² - x - 5 = 0

delta = (-1)² - 4.1.(-5)
delta = 1 + 20
delta = 21


x = -(-1) ± √21/2.1

x = 1 ± √21/2


s={ (1 - √21)/2, (1 + √21)/2 }