Question

Resolva as equações. A incógnita esta indicada entre parênteses:

b/a = d/c. ( a )


A = 1/2 (b+c) h. ( h)


A = 1/2bh. (b)


c = 2zr. (z)

2
A= a/360kr. (a)

Answer 1

a)

$\dfrac{b}{a} =\dfrac{d}{c} \\ad=bc\rightarrow\:\bf{a=\dfrac{b.c}{d}}$

b)

$A=\dfrac{1}{2}(b+c).h\\(b+c).h=2A$

$\bf{h=\dfrac{2A}{b+c}}$

c)

$A=\dfrac{1}{2}.b.h\rightarrow\:\bf{b=\dfrac{2A}{h}}$

d)

$c=2zr\rightarrow\:\bf{z=\dfrac{c}{2r}}$

e)

$A=\dfrac{a}{360kr}\rightarrow\:\bf{a=360krA}$