Question

Resolva as equações a) (0,2)^x = 125 b) (1/4)^x-1=16^x+2

Answer 1

Resposta:

a)

${0.2}^{x} = 125$

$( { \frac{1}{5}) }^{x} = {5}^{3}$

${5}^{ - x} = {5}^{3}$

-x = 3 . (-1)

x = - 3

b)

$({ \frac{1}{4} )}^{x - 1} = {16}^{x + 2}$

${4}^{ - x + 1} = {4}^{2(x + 2)}$

- x + 1 = 2 (x + 2)

- x + 1 = 2x + 4

- x - 2x = 4 - 1

- 3x = 3 . (-1)

x = -3/3 = -1