Question

Resolva as as as questões a seguir:
A) *Anexado*
B) *Anexado*​

Answer 1

Resposta:

1) $y = 1$ e $x = 0$

2) $\left[\begin{array}{ccc}x =4 &y=-3\\t=3&z=5 \end{array}\right]$

Explicação passo a passo:

1) $se \left[\begin{array}{ccc}y&0\\0&x+y\end{array}\right] = I_2$  ⇒ $\left[\begin{array}{ccc}1&0\\0&1\end{array}\right]$  $y = 1$ e $x = 0$

2) $\left[\begin{array}{ccc}x&y\\3&2z\end{array}\right] + \left[\begin{array}{ccc}x&3\\t&z\end{array}\right] = \left[\begin{array}{ccc}8&0\\6&15\end{array}\right]$ ⇒ $\left[\begin{array}{ccc}x+x=8&y+3=0\\3+t=6&2z+z=15\end{array}\right]$ ⇒$\left[\begin{array}{ccc}2x=8&y=0-3\\t=6-3&3z=15\end{array}\right]$ ⇒ $\left[\begin{array}{ccc}x =\frac{8}{2} &y=-3\\t=3&z=\frac{15}{3} \end{array}\right]$ ⇒$\left[\begin{array}{ccc}x =4 &y=-3\\t=3&z=5 \end{array}\right]$