Question

resolva aquaçao do 2grau na forma de baskara: X² -8X +12=0

Answer 1

x²-8x+12=0 sendo a=1,b=-8 e c=12

Δ = b²-4ac = (-8)²-4(1)(12) = 64-48 = 16

x'=(-b+√Δ)/2a = (-(-8)+√16)/2(1) = (8+4)/2 = 12/2 = 6
x''=(-b-√Δ)/2a = (-(-8)-√16)/2(1) = (8-4)/2 = 4/2 = 2

x'=6 e x''=2

Answer 2

x² - 8x + 12 = 0

a = 1; b = - 8; c = 12

Δ = b² - 4ac
Δ = (-8)² - 4.1.12
Δ = 64 - 48
Δ = 16

x = - b +/- √Δ  = - ( - 8) +/- √16
          2a                  2.1

x = 8 + 4 = 12/2 = 6
        2

x = 8 - 4 = 4/2 = 2
        2

R.: x = 6 e x = 2