resolva a soma de fração
a)1/5+2/3+6/5
b)2/3+1/6+3/2
c)7/5+2/3+1/5
d)3/2+1/7+2/3
Me ajude, gente pfvr
Soluções para a tarefa
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Olá
Vamos lá,
a)1/5+2/3+6/5 mmc=3.5=15
3+ 10 + 18 31
= ---------------= ---
15 15
b)2/3+1/6+3/2 mmc=18
12+3+27 42 :2 21 :3 7
=-------------- = ---- = ----- = ----
18 18 :2 9 :3 3
c)7/5+2/3+1/5 mmc=15
21+10+3 34
= ------------- = ---
15 15
d)3/2+1/7+2/3 mmc = 2.3.7=42
62+6+28 96 :2 48 :3 16
= ------------- = ---- = ----- = ---
42 42 :2 21 : 3 7
Vamos lá,
a)1/5+2/3+6/5 mmc=3.5=15
3+ 10 + 18 31
= ---------------= ---
15 15
b)2/3+1/6+3/2 mmc=18
12+3+27 42 :2 21 :3 7
=-------------- = ---- = ----- = ----
18 18 :2 9 :3 3
c)7/5+2/3+1/5 mmc=15
21+10+3 34
= ------------- = ---
15 15
d)3/2+1/7+2/3 mmc = 2.3.7=42
62+6+28 96 :2 48 :3 16
= ------------- = ---- = ----- = ---
42 42 :2 21 : 3 7
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