Question

Resolva a seguinte integral: (x³-6x²+4x-1)dx

Answer 1

$\int (x^3-6x^2+4x-1)dx=\frac{x^4}{4}-6.\frac{x^3}{3}+4\frac{x^2}{2}-x+C=\\ \\ \boxed{\frac{x^4}{4}-2x^3+2x^2-x+C}$