Question

resolva a seguinte equaçao[              x^{2} -4x+3=0

Answer 1

$x^{2} -4x+3=0 \\ \\ \Delta = (-4)^2 - 4.1.3 \\ \Delta = 4 \\ \\ x = \frac{-(-4) \pm \sqrt{4} }{2.1} = \frac{4 \pm 2}{2} \\ \\ x' = \frac{4 + 2}{2}= 3 \\ \\ x'' = \frac{4 - 2}{2} = 1 \\ \\ \boxed{S = \{1;3\}}$