Question

Resolva a seguinte equação exponencial$(\frac{1}{9)} ^{2-x} =\sqrt{27}$

Answer 1

(1/9)^(2-x) = √27

[(3)^(-2)]^(2-x) = √3^3

(3)^(2x-4) = (3^3)^1/2

(3)^(2x-4) = 3^(3/2)

2x-4 = 3/2

x-2 = 3/4

x = 3/4+2

x = (3+8)/2

x = 21/2

Resposta: x = 21/2