Question

resolva a questão 3.....

Answer 1

$(x + 1) \times (x + 1) = (2x - 1) \times (2x - 1)$

${x}^{2} + x + x + 1 = 4 {x}^{2} - 2x - 2x + 1$

${x}^{2} + 2x + 1 = 4 {x}^{2} - 4x + 1$

$4 {x}^{2} - 4x + 1 - 1 - 2x - {x}^{2} = 0$

$3 {x}^{2} - 6x = 0$
$3x(x - 2) = 0$

$x = 0$

$ou$

$x - 2 = 0$
$x = 2$