Question

resolva a integral (int 6t² 3√ t dt) "raiz cubica de t"

Answer 1

Bom dia 

∫ 6t² * ³√t dt

t² * ³√t = t^(2 +1/3) = t^(7/3)

∫ 6t² * ³√t dr = ∫ 6*t^(7/3) dt = 6/(10/3) * t^(10/3) + C

∫ 6t² * ³√t dt = 9/5  * t^(10/3) + C