Question

Resolva a integral definida

Answer 1

Resposta:

a) ~ 41510,4 u.a.

b) ~ 29,2 u.a.

Explicação passo-a-passo:

Bem, entendi que é pra resolver a questão 4.

Sendo assim, temos:

a)

8

∫ (x⁵- x³- 2x) dx =

-3

8

x⁶/6 - x⁴/4 - 2.x²/2 | =

-3

8

x⁶/6 - x⁴/4 - x²/ | =

-3

(8⁶/6 - 8⁴/4 - 8²) - ((-3)⁶/6 - (-3)⁴/4 - (-3)²) =

(131072/3 - 1024 - 64) - (243/2 - 81/4 - 9) =

131072/3 - 1024 - 64 - 243/2 + 81/4 + 9 =

~ 41510,4 u.a.

b)

9

∫ (x + √x - 1/∛x) dx =

6

9

∫ (x + x^½ - x^(-⅓)) dx =

6

9

x²/2 + (x^(3/2))/(3/2) - (x^(2/3))/(2/3) | =

6

9

x²/2 + (2/3).x^(3/2) - (3/2).x^(2/3) | =

6

9²/2 + (2/3).9^(3/2) - (3/2).9^(2/3) -

6²/2 - (2/3).6^(3/2) + (3/2).6^(2/3) =

81/2 + (2/3).(√9)³ - (3/2).9^(2/3) -

36/2 - (2/3).(√6)³ + (3/2).6^(2/3) =

45/2 + (2/3).(27 - √6³) - (3/2).(9^⅔ - 6^⅔) =

~ 29,2 u.a.

Blz?

Abs :)