Question

Resolva a inequação:$\frac{1-2x}{3}-\frac{x-2}{4}\leq \frac{x}{2}+\frac{1+x}{3}$

Answer 1

$\frac{1 - 2x}{3} - \frac{x - 2}{4} \leqslant \frac{x}{2} + \frac{1 + x}{3}$

$mmc = 12</p><p>[tex]4.(1 - 2x) - 3(x - 2) \leqslant 6x + 4(1 + x) =$

$4 - 8x - 3x + 6 \leqslant 6x + 4 + 4x =$

$- 8x - 3x - 6x - 4x = 4 - 6 - 4$

$- 23x = - 6 \: \: \: ( - 1) \\ 23x = 6 \\ x = \frac{6}{23}$