Question

Resolva a inequação log2 (x-5) + log2 (x-4) < 1

Answer 1

$\frac{log(x-5)}{log2} + \frac{log(x-4}{log2} < 1$
$\frac{log(x-5) + log(x-4)}{log2} < 1$
$log(x - 5 + x - 4) < log2$
$log(2x-9) < log2$
$2x-9 < 2$
$2x < 11$
$x < \frac{11}{2}$