Question

Resolva a fórmula de bhaskara:

$x {}^{2} - (3 + \sqrt{2} )x + 3 \sqrt{2 = 0}$
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Answer 1

Resposta:

Explicação passo-a-passo:

x²-(3+√2)x+3√2=0

Substitua os valores de a=1; b= -(3+√2) e c=3√2, na fórmula de Bhaskara:

$\Delta=[(b)^{2}-4(a)(c)=[-(3+\sqrt{2})]^{2}-4(1)(3\sqrt{2})=9+6\sqrt{2}+2-12\sqrt{2}=11-6\sqrt{2} \\\\x^{'}=\frac{-(b)-\sqrt{\Delta}}{2(a)}=\frac{-(-(3+\sqrt{2}))-\sqrt{11-6\sqrt{2}}}{2(1)}==\frac{(3+\sqrt{2})-\sqrt{11-6\sqrt{2}}}{2}\\\\x^{''}=\frac{-(b)+\sqrt{\Delta}}{2(a)}=\frac{-(-(3+\sqrt{2}))+\sqrt{11-6\sqrt{2}}}{2(1)}==\frac{(3+\sqrt{2})-\sqrt{11-6\sqrt{2}}}{2}$