Question

Resolva a expressão:
(0,5+0,333...).(7+0,4) / (0,75)-¹+0,75+(1,2)expoente 0
Ajudaa!!

Answer 1

$\frac{(0,5+0,333...).(7+0,4)}{(0,75)^-^1+0,75+(1,2)^0}=$

Resolvendo o Numerador:
$(\frac{5}{10 \fra}+ \frac{3}{9}).( \frac{74}{10}) }=$ (simplificando)

$( \frac{1}{2}+ \frac{1}{3}).( \frac{37}{5}=$

$(\frac{3+2}{6}). \frac{37}{5}=$

$\frac{37}{6}$

Resolvendo o denominador:

$( \frac{75}{100})^-^1+ \frac{75}{100}+1=$ (simplificando)

$( \frac{3}{4})^-^1+ \frac{3}{4}+1=$

$\frac{4}{3}+ \frac{3}{4}+1= \frac{16+9+12}{12}=$

= $\frac{37}{12}$

Numerador/denominador:

$\frac{ \frac{37}{6} }{ \frac{37}{12} }= \frac{37}{6}:[tex] \frac{37}{12}=$
   
$\frac{37}{6}. \frac{12}{37}= \frac{12}{6}=$

$2$