Question

Resolva a equações
A) 2x+3/5-40=5x-15

B) x [20-30(2-14)]=256

Me ajudem

Answer 1

Olá,

a)
$\frac{2x + 3}{5} - 40 = 5x - 15 \\ 2x + 3 - 200 = 25x - 75 \\ 2x - 197 = 25x - 75 \\ 2x - 25x = - 75 + 197 \\ - 23x = 122 \\ x = - \frac{122}{23}$

b)
$x(20 - 30(2 - 14) = 256 \\ x = \frac{256}{20 - 30(2 - 14)} \\ x = \frac{256}{20 - 30 \times ( - 12)} \\ x = \frac{256}{20 + 360} \\ x = \frac{256}{380} \\ x = \frac{64}{95}$

Espero ter te ajudado!

Answer 2

( 2x + 3)/5 - 40/1 = 5x/1 - 15 /1
mmc = 5
( 2X + 3 ) -   200  = 25X  - 75
2X - 25X  = -75 - 3 + 200
-23X  = 122
23X  = - 122
X = - 122/23 ***


b
x [ 20 - 30 ( 2 - 14 )] = 256
x [ 20 - 30 ( - 12 )] = 256
x [20 + 360 ]  = 256
X [ 380 ]  = 256
380X  = 256
X = 256/380    = 64/95  *****