Question

Resolva a equação utilizando Bhaskara x² - 4x – 5 = 0

Answer 1

se resolve assim:

x²-4x-5=0
a= 1 b=-4 c=-5
b²-4.a.c
(-4)²-4.1.(-5)
16+20
36

x= -b + ou - (raiz de delta que no caso é 36)/2
x= -(-4) + OU - raiz de 36/2
x= 4+ ou - 6/2

x'= 4+6/2 =10/2 = 5
x"=4-6/2 = -2/2 = -1

S = {-1, 5}

Answer 2

$x^{2} -4x - 5 = 0$

$x = \dfrac{-b \pm \sqrt{b^2 -4*a*c}}{2*a}$

a=1, b=−4, c=−5

Δ=b^2−4ac
Δ=(−4)2−4*(1)*(−5)
Δ=16+20
Δ=36

$x = \dfrac{-b \pm \sqrt{\triangle}}{2*a}$

$x = \dfrac{-(-4) \pm \sqrt{36}}{2*1} \\ \\ \\ x = \dfrac{4 \pm 6}{2} \\ \\ \\ x' = \dfrac{4 + 6}{2} \\ \\ \\ x' = \dfrac{10}{2} \\ \\ \\ x' = 5 \\ \\ \\ x'' = \dfrac{4 - 6}{2} \\ \\ \\ x'' = \dfrac{-2}{2} \\ \\ \\ x'' = -1$

S = {5, -1}