Question

Resolva a equação
$\frac{1}{x}$ = $\frac{x}{x + 2}$

Answer 1

$x^{2}=x+2 \\ x^{2} -x-2=0 \\\\ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \\ \\ x = \frac{1 \pm \sqrt{9}}{2} \\ \\ \boxed{\boxed{x'=2\ |\ x''=-1}}& \end{matrix}\right.$