Question

resolva a equação logaritmica log (2×-1) = log 5 na base 3 me ajudem por favozinho ​

Answer 1

Resposta:

Se for log (2x-1) =log₃ 5

log (2x-1) =log₃ 5

log (2x-1) =log 5 /log 3

log 3 * log (2x-1)= log 5

log (2x-1)^(log 3) =log 5

(2x-1)^(log 3)  = 5

2x-1 =5^(1/log 3)

2x =1+5^(1/log 3)

x=1/2 + (1/2)* 5^(1/log 3)

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Se for log₃ (2x-1) =log₃ 5

2x-1=5

2x=6

x=3