Question

Resolva a equação de 2o grau: x²-6x+9=0

Answer 1

∆= b²-4ac
∆= (-6)²- 4•1•9
∆= 36-36
∆= 0 existe uma raiz real

x= -b/2•a
x= -(-6)/2•1= 6/2 = 3


S{3}

Answer 2

x²-6x+9=0

A= 1 / B= -6 / 9

Δ=B²-4×A*C
Δ=(-6)²-4×1*9
Δ= 36-36
Δ= 0

X=-B⁺₋√Δ ÷ 2×A
X=-(-6)⁺₋√0 ÷ 2×1
X=6⁺₋0 ÷ 2

X¹= 6+0 ÷ 2
X¹= 6 ÷ 2
X¹= 3

X² =6-0 ÷ 2
X²=6 ÷ 2
X²= 3

S= (3)