Question

Resolva a equação 5x2+6x+1=0

Answer 1

Utilizando a formula de bhaskara 

$5x^{2} +6x+1 = 0$
Δ = b² - 4.a.c *
Δ = 6² - 4.5.1
Δ = 36 - 20
Δ = 16

x = $\frac{-b +- \sqrt{delta} }{y.a}$ *
x = $\frac{-36 +- \sqrt{16} }{2.5}$

$\left \{ {{x'= \frac{-36+4}{10} = \frac{32}{10} = -3,2} \atop {x''= \frac{-36 - 4}{10} = \frac{-40}{10} = -4 }} \right.$