Question

Resolva a biquadrada a seguir :::

Answer 1

4x^4-13x^2+3=0
x^2=y

4y^2-13y+3=p0
a=4
b=-13
c=3

delta= b^2-4ac
= (-13)^2-4.4.3
= 169-48
=121

Y= -b+- raiz de delta/2a
Y= -(-13) +-raiz de 121/2.4
Y= 13+-11/8

Y1=13+11/8
Y1=24/8
Y1= 3

Y2= 13-11/8
Y2= 2/8
Y2= 1/4

x^2=y1
x^2= 3
x1= raiz de 3

x^2=y2
x^2= 1/4
x2= raiz de 1/4
x2= 1/2