Question

resolva a bhaskara
${y}^{2} - 16y + 64 = 0$
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Answer 1

Resposta:

y1= y2= 8

Explicação passo-a-passo:

Δ=$-16^{2} -4. 1. 64$

Δ=$256-256=$

Δ=0

y= $\frac{-(-16) ±\sqrt{\\0}  }{2.1}$

y=$\frac{16±0}{2}$

y1=$\frac{16+0}{2}$ ∴ y1= $\frac{16}{2}$ = 8

y2= $\frac{16-0}{2}$ ∴ y2= $\frac{16}{8}$ = 8