Question

resolva:
4^x + 4*2^x - 32 =0

Answer 1

Resposta:

x=log2 (1+$\sqrt{113\\}$)-1

Explicação passo-a-passo:

(2²)^x +4-2^x -32=0

(2^x)² +4-2^x -32=0

t²+4-t-32=0

t=$\frac{1+\sqrt{113} }{2}$

t=$\frac{1-\sqrt{113} }{2}$

2^x=$\frac{1+\sqrt{113} }{2}$

2^x=$\frac{1-\sqrt{113} }{2}$

x=log${2}$(1+$\sqrt{113}$)-1

x∉|R