Question

resolva
4× (ao quadrado) +20x+25=0

Answer 1

4x^2 + 20x + 25 = 0
FORMULA BASKARA
a=4. b=20. c= 25
delta = b^2 - 4 a c
delta = (20)^2 - 4(4)(25)
delta = 400 - 16(25)
delta = 400 - 400
delta = 0
x = - b +,- \/delta/2a
x = - 20 +,- \/0/2(4)
x = - 20 +,- 0 /8
x1 = - 20 + 0/8》x1 = 20/8》x1 = 2,50
x2 = -20 - 0/8》x2 = -20/8》x2 = -2,50