Question

resolva 3x2-15x+12=0

Answer 1

Resolvendo por Bháskara:

$3x^2 - 15x + 12 = 0$

$x = \dfrac{-b \pm \sqrt{b^2 -4*a*c}}{2*a}$

a = 3. b = -15, c = 12

Δ=b²−4ac
Δ=(−15)²−4*3*12
Δ=225−144
Δ=81

$x = \dfrac{-b \pm \sqrt{\triangle}}{2*a} \\ \\ \\ x = \dfrac{-(-15) \pm \sqrt{81}}{2*3} \\ \\ \\ x = \dfrac{15 \pm 9}{6} \\ \\ \\ x' = \dfrac{15 + 9}{6} \\ \\ \\ x' = \dfrac{24}{6} \\ \\ \\ x' = 4 \\ \\ \\ x'' = \dfrac{15 - 9}{6} \\ \\ \\ x'' = \dfrac{6}{6} \\ \\ \\ x'' = 1$


S = {4, 1}