Question

Resolva 2y²-14y+12=0

Answer 1

2y^2 - 14y + 12 = 0

a = 2
b = - 14
c = 12

Delta = b^2 - 4.a.c
Delta = (- 14) - 4.2.12
Delta = 196 - 96
Delta = 100

y = - b +- VDelta / 2.a
y = - (- 14) +- V100 / 2.2
y = 14 +- 10 / 4

y' = 14 - 10 / 4
y' = 4/4
y' = 1

y" = 14 + 10 / 4
y" = 24/4
y" = 6

S = { 1, 6 }

Answer 2

Δ=b²-4.a.c
Δ=(-14)²-4.2.12
Δ=196-96
Δ=100

x=-b₊⁻√Δ 
       2.a
x=14₊⁻√100
       2.2
x=14₊⁻10
        4
 x=14+10= 24 =6
        4          4

x=14-10= 4=1
        4       4