Question

Resolva: (1+4k)²+(1+2k)²=1

Answer 1

   (1 + 4k)² + (1 + 2k)² = 1
    1 + 8k + 16k² + 1 + 4k + 4k² = 1
     20k² + 12k + 2 = 1
     20k² + 12k + 2 - 1 = 0
     20k² + 12k + 1 = 0
 
    Δ= 144-80 = 64
   √Δ= ±√64 = ±8
  
  k' = (-12+8)/40 = -4/40 = -1/10
 k" = (-12-8)/40  = -20/40 = -1/2
   
  Resposta:
                   k = -1/10   e/ou  k = -1/2