Question

Resolução das questões 6(2x-3)-5(x-2)=2(x+7) e 6x+7<9x+5.

Answer 1

$\# 1\\\\ 6(2x-3)-5(x-2)=2(x+7) \\\\ 12x-18-5x+10=2x+14 \\\\ 7x-8=2x+14 \\\\ 7x-2x=14+8 \\\\ 5x= 22 \\\\ \boxed{x=\frac{22}{5}} \\\\\\ \#2 \\\\ 6x+7<9x+5 \\\\ 6x-9x<5-7 \\\\ -3x<-2 \ |(-1) \\\\ 3x>2 \\\\ x>\frac{2}{3} \\\\ \boxed{x\in (\frac{2}{3};\infty)}$

Answer 2

6( 2x - 3) - 5( x - 2) = 2( x + 7)
12x - 18 - 5x + 10 = 2x + 14
12x - 5x - 2x = 14 + 18 - 10
5x = 22
x = 22/5 ou x = 4,4

6x + 7 < 9x + 5
6x - 9x < 5 - 7
- 3x < - 2 (multiplicando por - 1)
3x > 2
x > 2/3 ou x > 0,6