Question

razões trigonométricas no triângulo retângulo​

Answer 1

a) x = 8.33

b) x = 13.1

c) x = 7.5

d) x = 15.625

$\sf {\Huge ——————— }$

$\sf \green{ Sen } \red{ = } \orange{\frac{Cateto \: oposto}{Hipotenusa} } \\ \sf \purple{ Cos} \pink{ = } \blue{\frac{Cateto \: adjacente}{Hipotenusa} }\\ \sf \green{ Tan} \red{ =} \pink{ \frac{Cateto\: oposto}{Cateto\: adjacente} }$

$\sf \green{ Tan(50) } \red{ = } \sf \purple{ \frac{x}{7} } \\ \sf \pink{ 1.19 } \blue{ = } \sf \green{\frac{x}{7} } \\ \sf \red{ 1.19 } \orange{ \times } \sf \purple{ 7} \pink{ = } \sf\blue{ x }\\ \sf \green{ 8.33}\sf \red{ = } \orange{ x}$

$\sf \green{ Sen(50) } \red{ = } \orange{ \frac{10}{x} } \\ \sf \purple{ 0,76} \pink{= } \blue{ \frac{10}{x} }\\ \sf \green{ 0,76x} \red{ =} \orange{ 10} \\ \sf \purple{x } \pink{ = } \sf\blue{ \frac{10}{0,76} } \\ \sf \green{x } \sf \red{= } \orange{ 13.1 }$

$\sf \green{ Tan(50) } \red{ = } \orange{ \frac{9}{x} } \\ \sf \purple{ 1,19 } \pink{ = } \blue{\frac{9}{x} }\\ \sf \green{ 1,19x } \red{ = } \orange{9 } \\ \sf \purple{ x} \pink{ = } \sf\blue{ \frac{9}{1,19} } \\\ \sf \green{ x } \sf \red{ = } \orange{ 7.5 }$

$\sf \green{ Cos (50) } \red{= } \orange{ \frac{10}{x} } \\ \sf \purple{ 0,64} \pink{ = } \blue{ \frac{10}{x} }\\ \sf \green{ 0,64x} \red{ = } \orange{ 10 } \\ \sf \purple{ x } \pink{ = } \sf\blue{ \frac{10}{0,64} } \\ \sf \green{ x } \sf \red{= } \orange{ 15.625 }$