Question

rapidoooo
calcule a exreçao numerica ​

Answer 1

Resposta:

A)17

B)37

C)3

D)40

E)36

F)22

G)27

H)4

I)2

Explicação passo-a-passo:

A)2+8-3-5+15

10-3-5+15

7-5+15

2+15

17

B)12+[35-(10+2)+2]

12+[35-12+2]

12+[23+2]

12+25

37

C)[(18+3×2)÷8+5×3]÷6

[(18+6)÷8+5×3]÷6

[24÷8+5×3]÷6 =

[3+5×3]÷6

[3+15]÷6

18÷6

3

D)37+[29-(11+19-4)]

37+[29-(30-4)]

37+[29-26]

37+3

40

E)60÷{2+[8+18÷(17-8)]}+[(7×3)+(18÷2)+1]

60÷{2+[8+18÷(17-8)]}+[21+(18÷2)+1]

60÷{2+[8+18÷(17-8)]}+[21+9+1]

60÷{2+[8+18÷9]}+[21+9+1]

60÷{2+[8+2]}+[21+9+1]

60÷{2+10}+[21+9+1]

60÷{2+10}+[30+1]

60÷{2+10}+31

60÷12+31

5+31

36

F)8+{5+[(8+12)-(13-12)]-10}

8+{5+[20-(13-12)]-10}

8+{5+[20-1]-10}

8+{5+19-10}

8+{24-10}

8+14

22

G)3×{2×(19-15)-[5+(3-1)]+8}

3×{2×4-[5+(3-1)]+8}

3×{2×4-[5+2]+8}

3×[2×4-7+8}

3×[8-7+8}

3×[1+8}

3×9

27

H)[19+(32-5×6)]÷(5+2)+1

[19+(32-30)]÷(5+2)+1

[19+2]÷(5+2)+1

[19+2]÷7+1

21÷7+1

3+1

4

I)[7+(24-8)×2-5]÷[22-(3+2)]

[7+16×2-5]÷[22-(3+2)]

[7+16×2-5]÷[22-5]

[7+32-5]÷[22-5]

[39-5]÷[22-5]

34÷[22-5]

34÷17

2