Question

raízes da equação 10x-1=2x²+7

Answer 1

$2x^2-10x+8=0\\\\Simplificando\ os\ termos\\\\x^2-5x+4=0\\\\a=1\ \ \ \ \ b=-5\ \ \ \ c=4\\\\\triangle=b^2-4ac\\\triangle=(-5)^2-4\cdot(1)\cdot(4)\\\triangle=25-16\\\triangle=9\\\\\\b= \dfrac{-b \frac{+}{-} \sqrt{\triangle} }{2a}\\\\\\b= \dfrac{-(-5) \frac{+}{-} \sqrt{9} }{2}\\\\\\b= \dfrac{5 \frac{+}{-}3}{2}\\\\\\b'=4\\\\b"=1\\\\\boxed{S=\{1,4\}}$