Question

raiz quadrada de 2X-1 = X-1

Answer 1

$\sqrt{2x-1} = x-1\\ (\sqrt{2x-1})^2 = (x-1)^2\\ 2x - 1 = x^2 - 2x +1\\ x^2 - 4x + 2 = 0\\ Delta = 16 - 8\\ Delta = 8\\ x = \frac{4 +- \sqrt{8}}{2}\\ x = \frac{4+ \sqrt{8}}{2} \\ou\\ x = \frac{4 - \sqrt{8}}{2}$

Espero ter ajudado, bons estudos