Question

raiz, delta e bhascara, como resolvo? -2x^2+8x-8=0

Answer 1

-2x² + 8x - 8 = 0
A= - 2
B= 8
C= - 8

∆ = b² - 4ac

∆= 8² - 4 . (-2) . (-8)
∆= 64 - 64
∆ = 0

x = - b ± √∆ / 2a

x = - 8 ± √0 / 2 . (-2)
x = - 8 ± 0 / - 4

x'= - 8 + 0 / -4 = -8/-4 = 2
x'' = - 8 - 0/ - 4 = - 8/-4= 2

S={2}

Answer 2

-2x² + 8x - 8 = 0

a = - 2    b = 8   c =  - 8

delta;

Δ = b² - 4.a.c

Δ = 8² - 4 . (-2) . (-8)

Δ = 64 - 64

Δ = 0 → duas raízes iguais

baskara ;

x = - b +-√Δ /2.a

x = - 8 +- √ 0 / 2. (-2)

x = - 8 +- 0 / -4

x' = - 8 + 0/ - 4

x' =  -8/ -4

x' = 2

x'' = -8 - 0/ -4

x'' = - 8 / -4

x'' =  2

s={ x' = 2 e x'' = 2 }