Question

Racionalize: V5/V2 e 3/V5-V2

Answer 1

vamos lá....

$\frac{ \sqrt{5} }{ \sqrt{2} } = \frac{ \sqrt{5}. \sqrt{2} }{ \sqrt{2}. \sqrt{2} } = \frac{ \sqrt{10} }{ \sqrt{4} }= \frac{ \sqrt{10} }{2} \\ \\ \\ \frac{3}{ \sqrt{5}- \sqrt{2} } = \\ \\ \frac{3( \sqrt{5}+ \sqrt{2} ) }{( \sqrt{5} - \sqrt{2})( \sqrt{5} + \sqrt{2}) } = \\ \\ \frac{3( \sqrt{5}+ \sqrt{2}) }{ \sqrt{5^2} - \sqrt{2^2} } = \\ \\ \frac{3( \sqrt{5}+ \sqrt{2} ) }{5-2} = \frac{\not3( \sqrt{5}+ \sqrt{2} ) }{\not3} = \sqrt{5} +\sqrt{2}$

Answer 2

Resposta:

\begin{gathered} \frac{ \sqrt{5} }{ \sqrt{2} } = \frac{ \sqrt{5}. \sqrt{2} }{ \sqrt{2}. \sqrt{2} } = \frac{ \sqrt{10} }{ \sqrt{4} }= \frac{ \sqrt{10} }{2} \\ \\ \\ \frac{3}{ \sqrt{5}- \sqrt{2} } = \\ \\ \frac{3( \sqrt{5}+ \sqrt{2} ) }{( \sqrt{5} - \sqrt{2})( \sqrt{5} + \sqrt{2}) } = \\ \\ \frac{3( \sqrt{5}+ \sqrt{2}) }{ \sqrt{5^2} - \sqrt{2^2} } = \\ \\ \frac{3( \sqrt{5}+ \sqrt{2} ) }{5-2} = \frac{\not3( \sqrt{5}+ \sqrt{2} ) }{\not3} = \sqrt{5} +\sqrt{2} \end{gathered}

2

5

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2

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2

5

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2

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4

10

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2

10