Question

racionalize os denominadores:
$\frac{3}{ \sqrt{6} }$

$\frac{4}{3 \sqrt{2} }$
​

Answer 1

$\frac{3}{ \sqrt{6} } \times \frac{ \sqrt{6} }{ \sqrt{6} } = \frac{ 3\sqrt{6} }{ \sqrt{36} } = \frac{3 \sqrt{6} }{6} = \frac{ \sqrt{6} }{2} \\ \\ \frac{4}{3 \sqrt{2} } = \frac{4}{ \sqrt{18} } \times \frac{ \sqrt{18} }{ \sqrt{18} } = \frac{4 \sqrt{18} }{18} = \frac{2 \sqrt{18} }{9}$