Question

Racionalize os denominadores

ajudem!!!

Answer 1

Resposta:

$2\frac{\sqrt{3} }{9}$

Explicação passo-a-passo:

b) $\frac{2}{3\sqrt{3} }$= $\frac{2}{3\sqrt{3} } . \frac{3\sqrt{3}}{3\sqrt{3} } =$ $\frac{2}{3\sqrt{3} } \frac{3\sqrt{3}}{3\sqrt{3} } =$  $\frac{2}{3\sqrt{3} } \frac{3\sqrt{3}}{3\sqrt{3} } =\frac{2.3.\sqrt{3} }{3.3.\sqrt{3^{2} } }$ = $=\frac{2.3.\sqrt{3} }{3.3.\sqrt{3^{2} } }=\frac{6.\sqrt{3} }{9.3 } }= \frac{6.\sqrt{3} }{27 } } = \frac{2.\sqrt{3} }{9 } }$