Question

racionalize o denominador racionalize o denominador e simplifique quando for possível.


$a) \frac{2}{ \sqrt{6}}$

$b) \frac{ - 1}{2 \sqrt{5}}$

$c) \frac{14}{ \sqrt{7} }$

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Answer 1

Olá...

a)

2/√6 = 2/√6  /√6.√6 = 2√6 / 6 = √6/3

b)

- 1 / 2√5 = - 1√5 / 2√5 . 2√5 = - √5 / 2 × 5 = - √5 / 10

c)

14/√7 = 14√7 / √7.√7 = 14√7/7 = 2√7

Espero ter ajudado.

Answer 2

Resposta:

$a)\\ {2\over\sqrt{6} }={2\sqrt{6} \over\sqrt{6} .\sqrt{6} }={2\sqrt{6} \over\sqrt{36} }={2\sqrt{6} \over6}={\sqrt{6} \over3}\\ \\ b)\\ {-1\over2\sqrt{5} }={-1\sqrt{5} \over2.\sqrt{5} .\sqrt{5} }={-\sqrt{5} \over2.\sqrt{25} }={-\sqrt{5} \over2.5}={-\sqrt{5} \over10}\\ \\ c)\\ {14\over\sqrt{7} }={14\sqrt{7} \over\sqrt{7} .\sqrt{7} }={14\sqrt{7} \over\sqrt{49} }={14\sqrt{7} \over7}=2\sqrt{7}$