Question

racionalizando o denominador de ... temos​

Answer 1

$\dfrac{12}{ \sqrt{ {6}^{9} } } = \dfrac{12}{ \sqrt{ {6}^{2}{6}^{2}{6}^{2}{6}^{2}6 } } = \dfrac{12}{ \sqrt{ {6}^{2}} \sqrt{{6}^{2}} \sqrt{{6}^{2}} \sqrt{{6}^{2}} \sqrt{6} } \\ = \dfrac{12}{ 6 \cdot6\cdot6\cdot6 \sqrt{6} } = \dfrac{12}{ 1296 \sqrt{6} } = \dfrac{1}{108 \sqrt{6} } \\ = \dfrac{1}{108 \sqrt{6} } \cdot \dfrac{108 \sqrt{6} }{108 \sqrt{6} } = \dfrac{108 \sqrt{6} }{108 \cdot108 \cdot6 } \\ = \dfrac{ \sqrt{6} }{648 }$