Question

Questão: x²- 4√2x +3=0

Answer 1

$x^2-4\sqrt2x+3=0\\\\\Delta=b^2-4ac\\\Delta=(-4\sqrt2)^2-4\cdot1\cdot3\\\Delta=(-4)^2\sqrt{2^2}-12\\\Delta = 16\cdot2-12\\\Delta=32-12\\\Delta=20\\\\x = \dfrac{-b\pm\sqrt\Delta}{2a}\\\\x = \dfrac{-(4\sqrt2)\pm\sqrt{20}}{2\cdot1}\\\\x= \dfrac{-4\sqrt2\pm2\sqrt5}{2}\\\\x = \dfrac{2(-2\sqrt2\pm\sqrt5)}{2}\\\\x = -2\sqrt2\pm\sqrt5\\\\\\\\x_1 = -2\sqrt2+\sqrt5\\x_2 = -2\sqrt2-\sqrt5$