Matemática, perguntado por felipe982689, 3 meses atrás

questão de matemática

f(x)= x2 - 4x + 7

A) 56
B) 4
C) 53
D) 13

Soluções para a tarefa

Respondido por attard
2

\Large\displaystyle{}f\left(x\right) =  {x}^{2}  - 4x + 7 \\

Vamos lá:

A)

\Large\displaystyle{}f\left(56\right) =  {56}^{2}  - 4 \times 56 + 7 \\ \Large\displaystyle{}f\left(56\right) = 3136 - 4 \times 56 + 7 \\ \Large\displaystyle{}f\left(56\right) = 3136 - 224 + 7 \\ \Large\displaystyle{}f\left(56\right) = 2912 + 7 \\ \Large\displaystyle{}f\left(56\right) = 2919

B)

\Large\displaystyle{}f\left(4\right) =  {4}^{2}  - 4 \times 4 + 7 \\ \Large\displaystyle{}f\left(4\right) = 16 - 4 \times 4 + 7 \\ \Large\displaystyle{}f\left(4\right) = 16 - 16 + 7 \\ \Large\displaystyle{}f\left(4\right) = 0 + 7 \\ \Large\displaystyle{}f\left(4\right) = 7

C)

\Large\displaystyle{}f\left(53\right) =  {53}^{2}  - 4 \times 53 + 7 \\ \Large\displaystyle{}f\left(53\right) = 2809 - 4 \times 53 + 7 \\ \Large\displaystyle{}f\left(53\right) = 2809 - 212 + 7 \\ \Large\displaystyle{}f\left(53\right) = 2597 + 7 \\ \Large\displaystyle{}f\left(53\right) = 2604

D)

\Large\displaystyle{}f\left(13\right) =  {13}^{2}  - 4 \times 13 + 7 \\ \Large\displaystyle{}f\left(13\right) = 169 - 4 \times 13 + 7 \\ \Large\displaystyle{}f\left(13\right) = 169 - 52 + 7 \\ \Large\displaystyle{}f\left(13\right) = 117 + 7 \\ \Large\displaystyle{}f\left(13\right) = 124

\LARGE\displaystyle\text{$\begin{gathered} \underline{\boxed{\boldsymbol{{ \red{Bons}}  \blue{\:Estudos}}}}\end{gathered}$}

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